[Ilugc] Hacking a user's password in Unix
Bharathi Subramanian
sbharathi at MidasComm.com
Sun Apr 10 22:31:49 IST 2005
> echo '82 43/25 43+65P80P82P73P76P32P70P79P79P76P10P' | dc
Too Late ;-)
echo '65P80P82P73P76P32P70P79P79P76P10P' | dc
This is enough. Each number is equal to the ASCII value of each char
in the output and last 10 is new line char. Option P of DC will take
value from the stack and print it as char. Read the man dc. :)
Bye :)
--
Bharathi S
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